LESSON 6-5 PROBLEM SOLVING CONDITIONS FOR SPECIAL PARALLELOGRAMS

EFGH is a square. Unit 3 Jeopardy Review Part I. Example 2a CDFG is a rhombus. Show that the diagonals of square STVW are congruent perpendicular bisectors of each other. Since SV and TW have the same midpoint, they bisect each other. PQTS is a rhombus with diagonal Prove: What is the most precise name based on the markings?

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lesson 6-5 problem solving conditions for special parallelograms

My presentations Profile Feedback Log out. You can also prove that a given quadrilateral is a rectangle, rhombus, or square by using the definitions of the special quadrilaterals. The diagonals are congruent perpendicular bisectors of each other.

So a square has the properties of all three. Example 2b CDFG is a rhombus.

Geo 6.5 Conditions for Special Parallelograms PPT

TR CE 35 ft 29 ft. For complaints, use another form. To use this website, you must agree to our Privacy Policyincluding cookie policy. Feedback Privacy Policy Feedback. Applying Conditions for Special Parallelograms Determine if the conclusion is valid. Share buttons are a little bit lower. Why must ABCD be a rectangle?

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Properties of Special Parallelograms Warm Up Lesson Presentation – ppt video online download

What is the most precise name based on the markings? Example 1a Carpentry The rectangular gate has diagonal braces. Auth with social network: Give all the names that apply. Show that its diagonals are congruent perpendicular bisectors of each other. Name the polygon by the number of its sides. To prove that a given quadrilateral is a square, it is sufficient to show that the figure is both a rectangle and a rhombus.

6-4 Properties of Special Parallelograms Warm Up Lesson Presentation

If you wish to download it, please recommend it to your friends in any social system. MNRS is a rhombus. Holt Pfoblem Conditions for Special Parallelograms When you are given a parallelogram with certain properties, you can use the theorems below to determine whether the parallelogram is a rectangle.

lesson 6-5 problem solving conditions for special parallelograms

A rhombus is a quadrilateral with four congruent sides. Example 1b Carpentry The rectangular gate has diagonal braces. Unit 3 Jeopardy Review Part I. Use the diagonals to determine whether a parallelogram with vertices A 2, 7B 7, 9C 5, 4and D 0, 2 is a rectangle, rhombus, or square.

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lesson 6-5 problem solving conditions for special parallelograms

Upload document Create flashcards. Add this document to saved. Published by Lawrence Hunter Modified over 3 years ago. Subtract 20 from both sides and divide both sides by ABCD is a rhombus.

Since SV and TW have the same midpoint, they conditionz each other.

EFGH is a square. ABCD is a rhombus.

E is the midpoint ofand F is the midpoint of. You can add this document to your study collection s Sign in Available only to authorized users.